How can I simulate a diceroll up to 12 but exclude it being able to land on 1-6

pixelatedgentleman

Hi Folks,


Im using this code to simulate a diceroll.

(set: $diceroll = Math.ceil(Math.random()*12))

I want to be able to set it so it will roll up to 12 like it does here but will not be able to land on numbers 1-6

if anyone can help i'd be really grateful, thanks!

timsamoff

You could setup an if statement to take care of it:

(if: $diceroll <= 6)
[
(set: $diceroll to 0)
]

Or set $diceroll to whatever, of course.

Tim

TheMadExile

In general, something like the follow (otherwise you're buggering your distribution):

(set: $diceroll = Math.floor(Math.random() * (MAX - MIN + 1)) + MIN)

In your case, that would be (assuming you want a range of 7–12, inclusive):

(set: $diceroll = Math.floor(Math.random() * (12 - 7 + 1)) + 7)

timsamoff

Although, thinking about this further, couldn’t you just do something like:

(set: $diceroll to random(7,12))

Why is rolling 1-12 important in this case?

TheMadExile

Is the random() function available in Harlowe? If so, then simply use that (it should be functionally equivalent to my previous example code, if not exactly so).

timsamoff

Yes, it is.

mykael

So what are you trying to simulate?

6 + d6
rigged d12 - use 6 + d6 for an even distribution
rigged 2d6 - this is somewhat harder as 7 should be more common than 12

Try generating 0 to 20 and looking it up in this array:

[ 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 11, 11, 12 ]